Let X denote the number of doublets. X can take the value 0, 1, 2, or 3.
Possible doublets are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
Probability of getting a doublet =
Probability of not getting a doublet =
Now, P(X = 0) = P(no doublet) =
and
∴ the required probability distribution is